2013 JavaB2 马虎的算式

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1.题目描述

2.题目解析

• 这题最重要的就是这一句
• 可以采用枚举的方法实现
  

3.解题代码

import java.util.Calendar;

public class Test {
    public static void main(String[] args) {
        int counts = 0;
        for (int a = 1; a < 10; a++) {
            for (int b = 1; b < 10; b++) {
                if (b != a)
                    for (int c = 1; c < 10; c++) {
                        if (c != b && c != a)
                            for (int d = 1; d < 10; d++) {
                                if (d != a && d != b && d != c)
                                    for (int e = 1; e < 10; e++) {
                                        if (e != a && e != b && e != c && e != d) {
                                            if ((a * 10 + b) * (c * 100 + d * 10 + e) == (a * 100 + d * 10 + b) * (c * 10 + e)) {
                                                counts++;
                                                System.out.printf("(%d * 10 + %d) * (%d * 100 + %d * 10 + %d) = %d ", a, b, c, d, e, (a * 10 + b) * (c * 100 + d * 10 + e));
                                                System.out.printf("     (%d * 10 + %d) * (%d * 100 + %d * 10 + %d) = %d)\n", a, d, b, c, e, (a * 100 + d * 10 + b) * (c * 10 + e));
                                            }
                                        }
                                    }
                            }
                    }
            }
        }
        System.out.println("共计 " + counts + " 个");
    }
}

4.运行结果