BFS算法HDU - 1312 RED AND BLACK

http://acm.hdu.edu.cn/showproblem.php?pid=1312

#include<bits/stdc++.h>
using namespace std;
int n,m;
int ans;
int visit[200][200];
int dx[]= {-1,1,0,0};
int dy[]= {0,0,-1,1};
char maps[200][200];
struct s
{
    int x,y;//定义结构体减少冗余
};
void bfs(int x,int y)
{
    s a,b;
    queue<s>Q;
    a.x=x;
    a.y=y;
    Q.push(a);//吃进队列
    visit[x][y]=1;
    while(!Q.empty())
    {
        a=Q.front();
        Q.pop();
        for(int i=0; i<4; i++)
        {
            b.x=a.x+dx[i];
            b.y=a.y+dy[i];
            if(b.x>=1&&b.x<=n&&b.y>=1&&b.y<=m&&!visit[b.x][b.y]&&maps[b.x][b.y]=='.')
            {
                visit[b.x][b.y]=1;
                Q.push(b);
                //cout<<b.x<<" "<<b.y<<endl;
                ++ans;
            }
        }
    }

}
int main()
{
    while(cin>>m>>n&&m)
    {
        ans=0;
        int bx,by;
        memset(visit,0,sizeof(visit));
        for(int i=1; i<=n; i++)
        {
            for(int j=1; j<=m; j++)
            {
                cin>>maps[i][j];
                if(maps[i][j]=='@')
                {
                    bx=i,by=j;
                }
            }
        }
        for(int i=1; i<=n; i++)
        {
            for(int j=1; j<=m; j++)
            {
                if(maps[i][j]=='@')
                {
                    bx=i,by=j;
                    break;
                }
            }
        }
        bfs(bx,by);
        cout<<ans+1<<endl;//注意自身
    }
    return 0;
}

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转载自blog.csdn.net/lanshan1111/article/details/84136209