Triangle Partition
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 132768/132768 K (Java/Others)
Total Submission(s): 207 Accepted Submission(s): 115
Special Judge
Problem Description
Chiaki has 3n points p1,p2,…,p3n. It is guaranteed that no three points are collinear.
Chiaki would like to construct n disjoint triangles where each vertex comes from the 3n points.
Input
There are multiple test cases. The first line of input contains an integer T, indicating the number of test cases. For each test case:
The first line contains an integer n (1≤n≤1000) -- the number of triangle to construct.
Each of the next 3n lines contains two integers xi and yi (−109≤xi,yi≤109).
It is guaranteed that the sum of all n does not exceed 10000.
Output
For each test case, output n lines contain three integers ai,bi,ci (1≤ai,bi,ci≤3n) each denoting the indices of points the i-th triangle use. If there are multiple solutions, you can output any of them.
Sample Input
1
1
1 2
2 3
3 5
Sample Output
1 2 3
Source
2018 Multi-University Training Contest 1
Recommend
liuyiding | We have carefully selected several similar problems for you: 6308 6307 6306 6305 6304
#include<bits/stdc++.h>
using namespace std;
#define LL long long
const int MAXN = 1e5+10;
const int INF = 0x3f3f3f3f;
const int MOD = 1e9+7;
const int N = 1010;
struct node{
int x,y,id;
}p[MAXN];
int n,t;
bool cmp(node a,node b){
if(a.x == b.x)
return a.y < b.y;
return a.x < b.x;
}
int main(){
scanf("%d",&t);
while(t--){
scanf("%d",&n);
for(int i=1;i<=3*n;i++){
scanf("%d%d",&p[i].x,&p[i].y);
p[i].id = i;
}
sort(p+1,p+1+3*n,cmp);
for(int i = 1; i <= n*3; i+=3) {
printf("%d %d %d\n",p[i].id,p[i+1].id,p[i+2].id);
}
}
return 0;
}