Leetcode 53 最大子串和

给定数列 nums

dp[i] ——以nums[i]为结尾的子串的最大和 ***

开始：dp[0]=nums[0]

状态转移：dp[i] = max( dp[i-1]+nums[i],nums[i] )

class Solution {
public:
    static const int INF = 0x7fffffff;
    int maxSubArray(vector<int>& nums) {
        int len = nums.size();
        int maxn = INF*(-1);
        vector<int> dp(len);
        if (nums.size() == 0)return 0;
        for (int i = 0;i < len;i++) {
            if (i == 0) dp[0] = nums[0];
            else
            dp[i] = max(nums[i] + dp[i - 1], nums[i]);
            if (dp[i] > maxn)maxn = dp[i];
        }
        return maxn;
    }
};