线性代数:矩阵的四种乘法

AB=C

shape: A mxn , B nxp, C mxp

1、Cij=(row i of A)* (column j of B)

2、Matrix A times every column of B

A[b1 ... bp]=[Ab1 ... Abp]

3、Every row of A times matrix B

[row i of A] B= [row i of AB]

4、multiply column 1 to n of A times row 1 to n, add these matrices

AB= (column 1 of A ) (row 1 of B) +(column 2 of A)(row 2 of B) +... + (column n of A) ( row n of B)

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转载自blog.csdn.net/qq_40436147/article/details/87611739