MIT_单变量微积分_17

版权声明: https://blog.csdn.net/qq_38386316/article/details/88625100

1.微积分第一基本定理

注释:
如果 F ( x ) = f ( x ) F'(x)=f(x) ,则 a b f ( x ) d x = F ( a ) F ( b ) = F ( x ) a b \int_a^bf(x)dx=F(a)-F(b)=F(x)|_a^b

Ex: F ( x ) = x 3 3 F(x)=\frac{x^3}{3}

F ( x ) = x 2 = f ( x ) , a b f ( x ) d x = F ( a ) F ( b ) = b 3 3 a 3 3 F'(x)=x^2=f(x),\int_a^bf(x)dx=F(a)-F(b)=\frac{b^3}{3}-\frac{a^3}{3}

a = 0 , a b x 2 d x = x 3 3 0 b = b 3 3 当a= 0时,\int_a^bx^2dx=\frac{x^3}{3}|_0^b=\frac{b^3}{3}

Ex: s i n x x 0 > π sinx函数与x轴的阴影面积。(0->\pi)
0 π s i n x d x = ( c o s π ) 0 π = 1 + 1 = 2 \int_0^\pi sinxdx=(-cos \pi)|_0^\pi = 1+1=2

2.定积分的几何意义:

x轴上方面积 - x轴下方面积。

3.性质

  • a b ( f ( x ) + g ( x ) ) d x = a b f ( x ) d x + a b g ( x ) d x \int_a^b(f(x) +g(x))dx=\int_a^bf(x)dx+\int_a^bg(x)dx
  • a b C f ( x ) d x = C a b f ( x ) d x \int_a^bCf(x)dx=C\int_a^bf(x)dx
  • a b f ( x ) d x + b c f ( x ) d x = a c f ( x ) d x \int_a^bf(x)dx+\int_b^cf(x)dx=\int_a^cf(x)dx
  • a a f ( x ) d x = 0 \int_a^af(x)dx=0
  • a b f ( x ) d x = b a f ( x ) d x \int_a^bf(x)dx=-\int_b^af(x)dx
  • 积分估计:

如果 f ( x ) > g ( x ) f(x)>g(x) ,则 a b f ( x ) d x a b g ( x ) d x ( a < b ) \int_a^bf(x)dx\leq\int_a^bg(x)dx(a<b)

Ex: e x 1 x 0 e^x\geq 1,x \geq 0 .
a b e x d x a b 1 d x \int_a^be^xdx \geq \int_a^b1dx
e b 1 b e^b-1 \geq b
e b 1 + b e^b \geq 1+b

Ex: e x 1 + x , x 0 e^x \geq1+x,x \geq0
0 b e x d x 0 b ( 1 + x ) d x \int_0^be^xdx \geq \int_0^b(1+x)dx
e b 1 b + b 2 2 e^b-1 \geq b+\frac{b^2}{2}
e b b + 1 + b 2 2 e^b\geq b+1+\frac{b^2}{2}

  • 变量替换:

u 1 u 2 g ( u ) = x 1 x 2 g ( u ( x ) ) u ( x ) d x \int_{u_1}^{u_2}g(u)=\int_{x_1}^{x_2}g(u(x))u'(x)dx

Ex: 1 2 ( x 3 + 2 ) 5 x 2 d x \int_1^2(x^3+2)^5x^2dx

u = x 2 + 2 , d u = 3 x 2 u=x^2+2,du=3x^2
原式 = 3 10 u 5 1 3 d u =\int_3^{10}u^5\frac{1}{3}du
= 1 18 u 6 3 10 = 1 0 6 18 3 6 18 =\frac{1}{18}u^6|_3^{10}=\frac{10^6}{18}-\frac{3^6}{18}

Wanning:
1 1 x 2 d x = 1 1 u 1 2 u d u = 0 u = x 2 , d u = 2 x d x . d x = d u 2 x \int_{-1}^{1}x^2 dx =\neq \int_1^1u\frac{1}{2\sqrt{u}}du=0\\ u=x^2,du=2xdx.\\ dx=\frac{du}{2x}

u = x 2 , u ( x ) = 2 x { > 0 , ( x > 0 ) < 0 , ( x < 0 ) u=x^2,u'(x)=2x \left\{\begin{matrix} & >0, &(x>0) \\ & <0, &(x<0) \end{matrix}\right.

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