51nod 2383 高维部分和

题目
题面值得学习一下
多维前缀和:

for (i=1;i<=n;i++)
    for (j=1;j<=n;j++)
        for (k=1;k<=n;k++) a[i][j][k]+=a[i][j][k-1];
for (i=1;i<=n;i++)
    for (j=1;j<=n;j++)
        for (k=1;k<=n;k++) a[i][j][k]+=a[i][j-1][k];
for (i=1;i<=n;i++)
    for (j=1;j<=n;j++)
        for (k=1;k<=n;k++) a[i][j][k]+=a[i-1][j][k];

Code

#include<bits/stdc++.h>
using namespace std;
int i,n,s[1<<20],j;
inline char gc(){
	static char buf[100000],*p1=buf,*p2=buf;
	return p1==p2&&(p2=(p1=buf)+fread(buf,1,100000,stdin),p1==p2)?EOF:*p1++;
}
inline int rd(){
	int x=0,fl=1;char ch=gc();
	for (;ch<48||ch>57;ch=gc())if(ch=='-')fl=-1;
	for (;48<=ch&&ch<=57;ch=gc())x=(x<<3)+(x<<1)+(ch^48);
	return x*fl;
}
inline void wri(int a){if(a>=10)wri(a/10);putchar(a%10|48);}
inline void wln(int a){if(a<0)a=-a,putchar('-');wri(a),puts("");}
int main(){
	n=rd();
	for (i=0;i<n;i++) s[i]=rd();
	for (j=1;j<n;j<<=1)//枚举维度
		for (i=0;i<n;i++)//枚举所有数
			if (i&j) s[i]+=s[i^j];
	for (i=0;i<n;i++) wln(s[i]);
}

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转载自blog.csdn.net/xumingyang0/article/details/85164829
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