PAT (Advanced Level) Practice 1117 Eddington Number (25 分)

版权声明:本文为博主原创文章,未经博主允许不得转载。 https://blog.csdn.net/Nightmare_ak/article/details/84797859

二分

#include<cstdio>
using namespace std;

const int N=1e5+5;

int n,a[N];

int check(int x)
{
    int num=0;
    for(int i=1;i<=n;i++)
        if(a[i]>x)
            num++;
    return num>=x;
}

int main()
{
    scanf("%d",&n);
    for(int i=1;i<=n;i++)
        scanf("%d",a+i);
    int l=1,r=n+1;
    while(l<r)
    {
        int mid=(l+r)>>1;
        if(check(mid)) l=mid+1;
        else r=mid;
    }
    printf("%d\n",l-1);
    return 0;
}

猜你喜欢

转载自blog.csdn.net/Nightmare_ak/article/details/84797859