原题目:
原题链接:https://www.patest.cn/contests/pat-a-practise/1117
1117. Eddington Number(25)
“British astronomer Eddington liked to ride a bike. It is said that in order to show off his skill, he has even defined an “Eddington number”, E – that is, the maximum integer E such that it is for E days that one rides more than E miles. Eddington’s own E was 87.
Now given everyday’s distances that one rides for N days, you are supposed to find the corresponding E (<=N).
Input Specification:Each input file contains one test case. For each case, the first line gives a positive integer N(<=105), the days of continuous riding. Then N non-negative integers are given in the next line, being the riding distances of everyday.
Output Specification:
For each case, print in a line the Eddington number for these N days.
Sample Input:
10
6 7 6 9 3 10 8 2 7 8
Sample Output:
6
题目大意
找出存在的数E,使得存在E天Eddington的里程达到了E miles,使E尽可能得大。
解题报告
先排序,再把E从N到0进行检测,找到即停。
代码
/*
* Problem: 1117. Eddington Number(25)
* Author: HQ
* Time: 2018-03-11
* State: Done
* Memo:
*/
#include "iostream"
#include "vector"
#include "algorithm"
using namespace std;
vector<int> dis;
int N;
int main() {
cin >> N;
int x;
for (int i = 0; i < N; i++) {
cin >> x;
dis.push_back(x);
}
sort(dis.begin(), dis.end());
int i;
for (i = N; i > 0; i--) {
if (dis[N - i] > i) {
break;
}
}
cout << i << endl;
system("pause");
}