1087 有多少不同的值 python

思路是a是逐渐增大的一个数，所以只要a发生变化，a的计算结果就一定没出现过，所以count+1.
n = int(input())
tem = -1
count = 0
for i in range(1,n+1):
    a = i//2 + i//3 + i//5
    if tem != a:
        count += 1
        tem = a
print(count)