This is a problem given in the Graduate Entrance Exam in 2018: Which of the following is NOT a topological order obtained from the given directed graph? Now you are supposed to write a program to test each of the options.
Input Specification:
Each input file contains one test case. For each case, the first line gives two positive integers N (≤ 1,000), the number of vertices in the graph, and M (≤ 10,000), the number of directed edges. Then M lines follow, each gives the start and the end vertices of an edge. The vertices are numbered from 1 to N. After the graph, there is another positive integer K (≤ 100). Then K lines of query follow, each gives a permutation of all the vertices. All the numbers in a line are separated by a space.
Output Specification:
Print in a line all the indices of queries which correspond to "NOT a topological order". The indices start from zero. All the numbers are separated by a space, and there must no extra space at the beginning or the end of the line. It is graranteed that there is at least one answer.
Sample Input:
6 8
1 2
1 3
5 2
5 4
2 3
2 6
3 4
6 4
5
1 5 2 3 6 4
5 1 2 6 3 4
5 1 2 3 6 4
5 2 1 6 3 4
1 2 3 4 5 6
Sample Output:
3 4
#include <iostream>
#include <algorithm>
#include <cmath>
#include <vector>
#include <queue>
#include <stack>
#include <map>
#include <set>
#include <string>
#include <cctype>
#include <string.h>
#include <cstdio>
#include <unordered_set>
using namespace std;
int main() {
int n,m;
cin>>n>>m;
vector<int> v[1010];
vector<int> in(1010);
for(int i=0;i<m;i++){
int a,b;
cin>>a>>b;
v[a].push_back(b);
in[b]++;
}
int k,flag1=0;
cin>>k;
for(int i=0;i<k;i++){
vector<int> t=in;
int temp,flag=1;
for(int j=0;j<n;j++){
cin>>temp;
if(t[temp]) flag=0;
for(int k=0;k<v[temp].size();k++)
t[v[temp][k]]--;
}
if(flag==1) continue;
printf("%s%d",flag1==1?" ":"",i);
flag1=1;
}
return 0;
}