题面
题解
多重背包问题:每个物品是有限个
代码
#include<bits/stdc++.h>
using namespace std;
const int N = 1010;
int n, m;
int v[N], w[N], s[N];
int f[N][N];
int main() {
cin >> n >> m;
for (int i = 1; i <= n; i++) cin >> v[i] >> w[i] >> s[i];
for (int i = 1; i <= n; i++) {
for (int j = 0; j <= m; j++) {
for (int k = 0; k <= s[i] && k * v[i] <= j; k++) {
f[i][j] = max(f[i][j], f[i - 1][j - k * v[i]] + k * w[i]);
}
}
}
cout << f[n][m] << endl;
return 0;
}