'''
输入一个正数s,打印出所有和为s的连续正数序列(至少含有两个数)。
例如,输入15,由于1+2+3+4+5=4+5+6=7+8=15,所以打印三个连续
序列,1-5,4-6,7-8
'''
class Solution:
def FindContinuousSequence(self, num):
# 要求至少是连续两个正数,所以输入的num不可能比3小
if num < 3:
return None
small, big = 1, 2
# 要求是连续的数,所以最大的数也只能是比num一半多一点
middle = num // 2 + 1
SumNum = 0 # 用来计算small和big以及之间的数的和
while big <= middle and small < big:
SumNum = self.CalculateSum(small, big)
# 如果找到就打印
if SumNum == num:
self.PrintContinuousSequence(small, big)
# 找到之后增加big来找下一个
big = big + 1
SumNum = self.CalculateSum(small, big)
# 如果小就扩大序列
if SumNum < num:
big = big + 1
# 如果大就缩小序列
if SumNum > num:
small = small + 1
# 用来计算small和big之间数的和
def CalculateSum(self, small, big):
Sum = 0
for i in range(small, big+1):
Sum = Sum + i
return Sum
# 用来进行打印
def PrintContinuousSequence(self, small, big):
for i in range(small, big + 1):
print(i)
test = Solution()
test.FindContinuousSequence(15)
Python剑指offer:和为s的连续整数序列
猜你喜欢
转载自blog.csdn.net/Einstellung/article/details/100045969
今日推荐
周排行