算法分析与设计课程——LeetCode刷题之Decode Ways

版权声明:本文为博主原创文章,未经博主允许不得转载。 https://blog.csdn.net/m0_38041038/article/details/78996908

题目:

A message containing letters from A-Z is being encoded to numbers using the following mapping:

'A' -> 1
'B' -> 2
...
'Z' -> 26

Given an encoded message containing digits, determine the total number of ways to decode it.

For example,
Given encoded message "12", it could be decoded as "AB" (1 2) or "L" (12).

The number of ways decoding "12" is 2.

答案:

class Solution {
public:
     int n = s.size();
    if(n == 0 || s[0] == '0') return 0;
    if(n == 1) return 1;
    int res = 0,fn_1 = 1,fn_2 = 1;
    for(int i = 1;i < n;i++){
        int temp = fn_1;
        if(isValid(s[i])&&isValid(s[i-1],s[i]))  res+=fn_1+fn_2;
        if(!isValid(s[i])&&isValid(s[i-1],s[i])) res+=fn_2;
        if(isValid(s[i])&&!isValid(s[i-1],s[i])) res+=fn_1;
        if(!isValid(s[i])&&!isValid(s[i-1],s[i]))  return 0;
        fn_1 = res;
        fn_2 = temp;
        res = 0;
    }
    return fn_1;
}
bool isValid(char a,char b){
    return a == '1'||(a == '2' && b <='6');
}
bool isValid(char a){
    return a != '0';
}
};


猜你喜欢

转载自blog.csdn.net/m0_38041038/article/details/78996908