排序--2-归并排序

参考:
http://cuijiahua.com/blog/2018/01/algorithm_7.html

算法思想

    该算法采用经典的分治(divide-and-conquer)策略(分治法将问题(divide)成一些小的问题然后递归求解,而治(conquer)的阶段则将分的阶段得到的各答案"修补"在一起,即分而治之


#include <iostream>
#include <vector>
using namespace std;

class Solution
{
public:
	void mergeSort(vector<int> &array)
	{
		int len = array.size();
		if (len <= 0)
			return;
		vector<int> temp(len);
		divide(array, 0, len - 1, temp);
	}
private:
	void divide(vector<int> &array, int left, int right, vector<int> temp)
	{
		if (left < right)
		{
			int mid = (left + right) / 2;
			divide(array, left, mid, temp);
			divide(array, mid + 1, right, temp);
			conquer(array, left, mid, right, temp);
		}
	}
	void conquer(vector<int> &array, int left, int mid, int right, vector<int> &temp)
	{
		int i = left;
		int j = mid + 1;
		int k = 0;
		while (i <= mid && j <= right)				//小的进入temp
		{
			if (array[i] <= array[j])
				temp[k++] = array[i++];
			else
				temp[k++] = array[j++];
		}
		while (i <= mid)
			temp[k++] = array[i++];				//如果前半段有剩余
		while (j <= right)
			temp[k++] = array[j++];				//如果后半段有剩余

		//array.assign(temp.begin(), temp.end());	
		k = 0;
		while (left <= right)
			array[left++] = temp[k++];
	}
};

int main()
{
	Solution s;
	vector<int> array{2, 3, 9, 6, 4, 5, 8};
	s.mergeSort(array);
	for (auto i : array)
		cout << i;
	cout << endl;
	system("pause");
	return 0;
}

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转载自blog.csdn.net/ax_hacker/article/details/80951624