CCF 折点计数(满分代码 + 解题思路 :找规律暴力模拟) 201604-1

解题思路

折点就是较高点或较低点
统计折点数量
当a[i] > a[i - 1] && a[i] > a[i + 1]时,该点为较高点,答案+ 1
当a[i] < a[i - 1] && a[i] < a[i + 1]时,该点为较低点,答案+ 1


代码实现

#include <iostream>
#include <cstring>
#include <algorithm>
#include <vector>
#include <sstream>
#include <set>

using namespace std;

const int N = 1010;

int a[N];

int main()
{
    
    
    int n;
    cin >> n;

    for (int i = 1; i <= n; i ++) cin >> a[i];
    int res = 0;
    for (int i = 2; i < n; i ++)
    {
    
    
        if (a[i] > a[i - 1] && a[i] > a[i + 1]) res ++; //较高点
        if (a[i] < a[i - 1] && a[i] < a[i + 1]) res ++; //较低点
    }
    cout << res;
    return 0;
}

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转载自blog.csdn.net/qq_51800570/article/details/129150901