旅游规划之Dijkstra

#include <iostream>
using namespace std;
#define INFINITY 100000000
struct  gnode
{
    
    
	int weight;
	int expenses;


}G[500][500];
int nv, ne;
int sta, enk;
int visit[500] = {
    
     0 };
int dist[500], cost[500];
void build()
{
    
    //建立一个表
	int v1, v2, w, ex;
	for (int i = 0; i < nv; i++)
	{
    
    
		for (int j = 0; j < nv; j++)
		{
    
    
			G[i][j].expenses = INFINITY;
			G[i][j].weight = INFINITY;

		}
	}
	fill(dist, dist + nv, INFINITY);
	fill(cost, cost + nv, 0);
	for (int i = 0; i < ne; i++)
	{
    
    
		cin >> v1 >> v2 >> w >> ex;
		G[v1][v2].weight = w;
		G[v2][v1].weight = w;
		G[v1][v2].expenses = ex;
		G[v2][v1].expenses = ex;
	}
}
	void Dij()
	{
    
    
		dist[sta] = 0;
		while (1)
		{
    
    
			int v = -1;
			for (int u = 0; u < nv; u++)
			{
    
    
				if (!visit[u] && (v ==-1 || visit[u] < visit[v]))
					v = u;        
			}
			if (v == -1)
				break;
			visit[v] = 1;
			for (int w = 0; w < nv; w++)
			{
    
    
				if (dist[v] + G[v][w].weight < dist[w])
				{
    
    
					dist[w] = dist[v] + G[v][w].weight;
					cost[w] = cost[v] + G[v][w].expenses;

				}
				else if((dist[v] + G[v][w].weight == dist[w]) && (cost[v] + G[v][w].expenses < cost[w]))
				{
    
    
					cost[w] = cost[v] + G[v][w].expenses;

				}

			}

		}
	}
	int main()
	{
    
    
		cin >> nv >> ne >> sta >> enk;
		build();
		Dij();
		cout << dist[enk] << " " << cost[enk];
	}