为了简单，我们的图都是用二维数组进行存储
col1 col2 col3
row1 [ 0 1 0
row2 1 0 1
row3 0 1 0 ]
package graph;
/*矩阵初始化*/
public class Graph {
private int vexNum;
private String[] vexNode;
private int[][] matrix = new int[vexNum][vexNum];
public Graph(int vexNum, String[] vexNode, int[][] graph) {
this.vexNum = vexNum;
this.matrix = graph;
this.vexNode = vexNode;
}
// 获得第一个邻接点
public int getFirstAdjvex(int[][] matrix, int u) {
for (int i = 0; i < vexNum; i++) {
if (matrix[u][i] != 0) {
return i;
}
}
return -1;
}
// 反方向获得第一个邻接点
public int getReverseFirstAdjvex(int[][] matrix, int u) {
for (int i = 0; i < vexNum; i++) {
if (matrix[i][u] != 0) {
return i;
}
}
return -1;
}
// 获取下一个邻接点
public int getNextAdjvex(int[][] matrix, int u, int v) {
for (int i = v + 1; i < vexNum; i++) {
if (matrix[u][i] != 0) {
return i;
}
}
return -1;
}
// 获取下一个邻接点
public int getReverseNextAdjvex(int[][] matrix, int u, int v) {
for (int i = v + 1; i < vexNum; i++) {
if (matrix[i][u] != 0) {
return i;
}
}
return -1;
}
public int getVexNum() {
return vexNum;
}
public void setVexNum(int vexNum) {
this.vexNum = vexNum;
}
public int[][] getMatrix() {
return matrix;
}
public void setMatrix(int[][] graph) {
this.matrix = graph;
}
public String[] getVexNode() {
return vexNode;
}
public void setVexNode(String[] vexNode) {
this.vexNode = vexNode;
}
}
1 图的遍历
深度优先遍历
类似树的中序遍历，每次都访问第一个邻接点，把访问的节点置为已访问。如果，已经没有了第一个邻接点，则访问下一个邻接点。重复该过程。
广度优先遍历
每次访问一层邻接节点，一直往下访问
写算法
package graph.traverse;
import java.util.LinkedList;
import java.util.Queue;
import graph.Graph;
public class Traverse {
private Graph graph;
private boolean []isVisited=new boolean[100];
public void boardFirstSearch() {
for (int i = 0; i < graph.getVexNum(); i++) {
if (!isVisited[i]) {
boardFirstSearch(i);
}
}
}
private void boardFirstSearch(int i) {
int u,w;
Queue queue=new LinkedList<Integer>();
//1 当前节点下标如队列
queue.add(i);
System.out.print(graph.getVexNode()[i]+"-->");
while(!queue.isEmpty()){
u=(int) queue.remove();
isVisited[u]=true;
for(w=graph.getFirstAdjvex(graph.getMatrix(), u);w>=0;
w=graph.getNextAdjvex(graph.getMatrix(), u, w)){
if(!isVisited[w]){
System.out.print(graph.getVexNode()[w]+"-->");
isVisited[w]=true;
queue.add(w);
}
}
}
}
public void BFSFirstSearch() {
for (int i = 0; i < graph.getVexNum(); i++) {
if (!isVisited[i]) {
BFSFirstSearch(i);
}
}
}
private void BFSFirstSearch(int i) {
// TODO Auto-generated method stub
int w;
System.out.print(graph.getVexNode()[i]+"-->");
isVisited[i]=true;
for(w=graph.getFirstAdjvex(graph.getMatrix(), i);w>=0;
w=graph.getNextAdjvex(graph.getMatrix(), i, w)){
if(!isVisited[w]){
BFSFirstSearch(w);
}
}
}
public static void main(String[] args) {
System.out.println("图");
int vexNum=8;
String []vexNode={"V1","V2","V3","V4","V5","V6","V7","V8"};
int [][]matrix={{0,1,1,0,0,0,0,0},
{1,0,0,1,1,0,0,0},
{1,0,0,0,0,1,1,0},
{0,1,0,0,0,0,0,1},
{0,1,0,0,0,0,0,1},
{0,0,0,1,0,0,1,0},
{0,0,0,1,0,1,0,0},
{0,0,0,0,1,1,0,0}
};
Traverse bfs=new Traverse();
bfs.graph=new Graph(vexNum, vexNode, matrix);
for (int i=0;i<vexNum;i++){
bfs.isVisited[i]=false;
}
System.out.println("---------广度优先遍历---------");
bfs.boardFirstSearch();
for (int i=0;i<vexNum;i++){
bfs.isVisited[i]=false;
}
System.out.println("\r\n---------深度优先遍历---------");
bfs.BFSFirstSearch();
}
}
2 图的连通性和生成树
无向图
连通图：任意两个顶点可达
连通分量：无向图的极大连通子图
有向图
强连通图：任意两个顶点可达
强连通分量：极大强连通子图
生成树：一个连通图的生成树是一个极小连通子图，他包含图的所有顶点，但只有足以构成一棵树的n-1条边。添加一条边就形成环。生成树求解算法。
普里姆算法：
初始的U={v0},选择V-U各个节点到U={V0}的最短路径的节点{V0,V3},继续重复此过程，直到选择出n个节点。每次都选择一个最短的路径，那么生成树就是最小的。
package graph.traverse;
import java.util.HashSet;
import java.util.Set;
import graph.Graph;
public class MiniSpanTree {
// int [][]closeEdge,记录任意两个节点之间的权值,k代表起始节点的下标
public void miniTree(Graph graph, int k, CloseEdge[] closeEdge) {
int vexNum = graph.getVexNum();
// 带有权值的矩阵
int[][] matrix = graph.getMatrix();
closeEdge[k] = new CloseEdge();
// 1 目前U={k},求其他各个节点和U的节点之间的权值
for (int i = 0; i < vexNum; i++) {
if (i != k) {
closeEdge[i] = new CloseEdge();
closeEdge[i].lowcost = matrix[k][i];
closeEdge[i].adjvex = k;
}
}
for (CloseEdge is : closeEdge) {
if (is.lowcost == Integer.MAX_VALUE) {
System.out.print("∽ ");
} else {
System.out.print(is.lowcost + " ");
}
}
System.out.println();
Set U = new HashSet();
U.add(k);
//剩余n-1个节点
for (int i = 1; i < vexNum; i++) {
// 3 寻找U和V-U的节点权值的最小值
k = mininum(closeEdge, vexNum, U);
System.out.print("k="+k+" ");
U.add(k);
System.out.println(graph.getVexNode()[closeEdge[k].adjvex] + "-->" + graph.getVexNode()[k]);
closeEdge[k].lowcost = 0;
// 4 对U到U-V的各个节点的权值做一轮更新
for (int j = 0; j < vexNum; j++) {
if (matrix[k][j] < closeEdge[j].lowcost) {
closeEdge[j].lowcost = matrix[k][j];
closeEdge[j].adjvex = k;
}
}
for (CloseEdge is : closeEdge) {
if (is.lowcost == Integer.MAX_VALUE) {
System.out.print(" ∽ ");
} else {
System.out.print(is.lowcost + " ");
}
}
System.out.println();
}
}
private int mininum(CloseEdge[] closeEdge, int vexNum, Set U) {
// TODO Auto-generated method stub
int min = Integer.MAX_VALUE;
int index = 0;
for (int i = 1; i < vexNum; i++) {
// System.out.println(closeEdge[i]);
if (closeEdge[i].lowcost < min && closeEdge[i].lowcost != 0) {
min = closeEdge[i].lowcost;
index = i;
}
}
return index;
}
public static void main(String[] args) {
MiniSpanTree mst = new MiniSpanTree();
System.out.println("图");
int vexNum = 6;
int MAX = Integer.MAX_VALUE;
String[] vexNode = { "V1", "V2", "V3", "V4", "V5","v6"};
int[][] matrix = { { MAX, 6, 1, 5, MAX, MAX },
{ 6, MAX, 5, MAX, 3, MAX },
{ 1, 5, MAX, 5, 6, 4},
{ 5, MAX, 5, MAX, MAX, 2 },
{ MAX, 3, 6, MAX, MAX, 6 }, { MAX, MAX, 4, 2, 6, MAX }, };
Graph graph = new Graph(vexNum, vexNode, matrix);
CloseEdge[] closeEdge = new CloseEdge[vexNum];
mst.miniTree(graph, 0, closeEdge);
}
}
//V-U的节点到U的大小,随着节点的加入不断的进行更新
class CloseEdge {
int adjvex;
int lowcost;
}3 拓扑排序
不存在环。算法：给定每个节点入度，把入度为0的节点入队列，然后，节点出对列，把与这个节点相连的节点的入度-1，如果，节点入度为0也入队列。对列不空，继续重复这个过程。
package graph.traverse;
import java.util.Stack;
import graph.Graph;
public class TopologicalSort {
public boolean topologic(Graph graph) {
int[][] matrix = graph.getMatrix();
int vexNum = graph.getVexNum();
int[] indegree = new int[vexNum];
// 求各个节点的入度
for (int i = 0; i < vexNum; i++) {
for (int j = 0; j < vexNum; j++) {
if (matrix[i][j] != 0) {
indegree[j]++;
}
}
}
// 把入度为零的节点全部入栈
Stack stack = new Stack();
for (int i = 0; i < vexNum; i++) {
if (indegree[i] == 0) {
stack.push(i);
System.out.print(graph.getVexNode()[i] + " ");
}
}
// 栈不空的时候，一直出栈，并把和出栈节点相邻的节点的入度--。如果，为零也入栈
int count = 0;
while (!stack.isEmpty()) {
int u = (int) stack.pop();
count++;
for (int w = graph.getFirstAdjvex(matrix, u); w >= 0; w = graph.getNextAdjvex(matrix, u, w)) {
if (--indegree[w] == 0) {
stack.push(w);
System.out.print(graph.getVexNode()[w] + " ");
}
}
}
if (count != graph.getVexNum()) {
return false;
}
return true;
}
public static void main(String[] args) {
int vexNum = 4;
String[] vexNode = { "V1", "V2", "V3", "V4" };
int[][] matrix = {
{ 0, 1, 1, 0 },
{ 0, 0, 0, 1 },
{ 0, 0, 0, 1 },
{ 0, 0, 0, 0 } };
Graph graph = new Graph(vexNum, vexNode, matrix);
TopologicalSort ts=new TopologicalSort();
ts.topologic(graph);
}
}
4 关键路径
关键路径就是消耗时间最长的那条路径，如果这个路径完成，那么其他的路径都已经完成。算法：从开始节点出发，计算出每个节点的最早的到达时间ve，ve是由它前边的最长路径决定的。从终止节点往回走，计算出每个节点的最晚的到达时间vl，vl的初始值都设为终点的最早到达时间，然后，从终点-路径长度就是该点的路径长度。
如果，最早到达时间和最晚到达时间大小相等，那么这个点肯定在关键的路径上，这个节点没有任何时间调整的可能。
package graph.traverse;
import java.util.Stack;
import graph.Graph;
public class CriticalPath {
private Stack T=new Stack();
//每个节点开始的最早的时间，前边的都执行完才能执行该节点，因此，该节点是前边最长的那条路径长度
private int [] ve;
private int [] vl;
public boolean topologic(Graph graph) {
int[][] matrix = graph.getMatrix();
int vexNum = graph.getVexNum();
int[] indegree = new int[vexNum];
ve=new int [vexNum];
for(int i=0;i<vexNum;i++){
ve[i]=0;
}
// 求各个节点的入度
for (int i = 0; i < vexNum; i++) {
for (int j = 0; j < vexNum; j++) {
if (matrix[i][j] != 0) {
indegree[j]++;
}
}
}
// 把入度为零的节点全部入栈
Stack stack = new Stack();
for (int i = 0; i < vexNum; i++) {
if (indegree[i] == 0) {
stack.push(i);
}
}
// 栈不空的时候，一直出栈，并把和出栈节点相邻的节点的入度--。如果，为零也入栈
int count = 0;
while (!stack.isEmpty()) {
int u = (int) stack.pop();
//System.out.print(graph.getVexNode()[u] + " ");
T.push(u);
count++;
for (int w = graph.getFirstAdjvex(matrix, u); w >= 0; w = graph.getNextAdjvex(matrix, u, w)) {
if (--indegree[w] == 0) {
stack.push(w);
}
if(ve[u]+matrix[u][w]>ve[w]){
ve[w]=ve[u]+matrix[u][w];
}
}
}
if (count<graph.getVexNum()) {
return false;
}
return true;
}
public void critical(Graph graph){
int[][] matrix = graph.getMatrix();
int vexNum = graph.getVexNum();
int[] indegree = new int[vexNum];
vl=new int [vexNum];
//初始化各个节点的最迟发生时间
if(!topologic(graph)){
return;
}
for(int i=0;i<vexNum;i++){
vl[i]=ve[vexNum-1];
}
int u,w;
while(!T.isEmpty()){
u=(int)T.pop();
for(w=graph.getReverseFirstAdjvex(matrix, u);w>=0;w=graph.getReverseNextAdjvex(matrix, u, w)){
//往前推，使其前驱事件能够满足所有的后驱实践，这个应该是能发生的越早就越早
if(vl[w]>vl[u]-matrix[w][u]){
vl[w]=vl[u]-matrix[w][u];
}
}
}
for(int i=0;i<graph.getVexNum();i++){
if(ve[i]==vl[i]){
System.out.println(graph.getVexNode()[i]+" ");
}
}
}
public static void main(String[] args) {
int vexNum = 6;
String[] vexNode = { "V1", "V2", "V3", "V4","V5","V6"};
int[][] matrix = {
{ 0, 3, 2, 0, 0, 0 },
{ 0, 0, 0, 2, 3, 0 },
{ 0, 0, 0, 4, 0, 3 },
{ 0, 0, 0, 0, 0, 2 },
{ 0, 0, 0, 0, 0, 1 },
{ 0, 0, 0, 0, 0, 0 }
};
Graph graph = new Graph(vexNum, vexNode, matrix);
CriticalPath cp=new CriticalPath();
//cp.topologic(graph);
cp.critical(graph);
}
}
最短路径
迪杰斯特拉算法(一个节点到所有节点的最短路径)：贪婪算法，从一个节点出发，每次选一条最短的路径，这个最短的路径可能是（v,vk）或者是((v,vj),vk)
这个算法那网上有很多，就不在赘述。
弗洛伊德算法（任意两个节点之间的最短距离):每次以一个节点为桥，更新两个节点之间的最短距离
package graph.traverse;
import graph.Graph;
public class FlOYD {
public void shortPath(Graph graph){
int[][] matrix = graph.getMatrix();
int vexNum = graph.getVexNum();
int [][]D=new int [vexNum][vexNum];
boolean [][][]P=new boolean[vexNum][vexNum][vexNum];
//初始化
for(int i=0;i<vexNum;i++){
for(int j=0;j<vexNum;j++){
D[i][j]=matrix[i][j];
for(int u=0;u<vexNum;u++){
P[i][j][u]=false;
}
//记录i到j之间的路径
if(D[i][j]<Integer.MAX_VALUE){
P[i][j][i]=true;
P[i][j][j]=true;
}
}
}
//一个顶点一个顶点的矩阵中添加，不断的跟新矩阵
for(int u=0;u<vexNum;u++){
for(int v=0;v<vexNum;v++){
for(int w=0;w<vexNum;w++){
if(D[v][u]+D[u][w]<D[v][w]){
D[v][w]=D[v][u]+D[u][w];
//路径也要更新
}
}
}
for (int[] is : D) {
for (int i : is) {
System.out.print(i+" ");
}
System.out.println();
}
}
}
public static void main(String[] args) {
int vexNum = 3;
String[] vexNode = { "A", "B", "C"};
int MAX=Integer.MAX_VALUE;
int[][] matrix = {
{ 0, 4, 11},
{ 6, 0, 2},
{ 3, MAX, 0}
};
Graph graph = new Graph(vexNum, vexNode, matrix);
FlOYD f=new FlOYD();
f.shortPath(graph);
}
}
