class Solution {
public boolean canThreePartsEqualSum(int[] A) {
long sum = 0L;
for (int i = 0; i < A.length; ++i) {
sum += A[i];
}
if (sum % 3 != 0)
return false;
long ave = sum / 3, cur = 0L;
int count = 0;
for (int i = 0; i < A.length; ++i) {
cur += A[i];
// ans
if (count == 3)
return true;
// update
if (cur == ave) {
++count;
cur = 0L;
}
}
if (count == 3)
return true;
return false;
}
}
leetcode-1013. 将数组分成和相等的三个部分
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转载自blog.csdn.net/qq_39370495/article/details/89341030
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