hdu2669寒训D题Romantic

跟之前那个题基本一样,拓展欧几里得的模板题。不再赘述,以下为代码

#include<iostream>
#include<stdio.h>
using namespace std;
typedef long long ll;
ll exgcd(ll a,ll k,ll &x,ll &y)
{
    ll d=a;
    if(k!=0)
    {
        d=exgcd(k,a%k,y,x);
        y-=(a/k)*x;
    }
    else
    {
        x=1;
        y=0;
        if(a==1)return a;
        else return -1;
    }
    return d;
}
int main()
{
    ll a,k;
    while(scanf("%lld%lld",&a,&k)!=EOF)
    {
        ll x,y;
        if(exgcd(a,k,x,y)==-1)
            {printf("sorry\n");
            continue;}
        if(x<=0)
        {
            x+=k;
        }
        y=(1-x*a)/k;
        printf("%lld %lld\n",x,y);
    }
}

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转载自blog.csdn.net/weixin_43331783/article/details/88426401