求极限、等价无穷小

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python 自带常数E

解答:

x = Symbol('x')

limit(E,x,0)

解答:

x0 = Symbol('x0') #常数可省略

x = Symbol('x')

limit(x,x,x0)

解答:

x = Symbol('x')

limit((2*x-1),x,1)

解答:

x = Symbol('x')

limit((pow(x,2)-1)/(x-1),x,1)

解答:

x = Symbol('x')

x0 = Symbol('x0') #常数可省略

limit((pow(x,1/2)),x,x0)

解答:

n = Symbol('n')

x = Symbol('x')

limit((pow((1+x),1/n)-1)/(1/n*x),x,0) #等价无穷小

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转载自blog.csdn.net/zz__dm/article/details/82899803