LeetCode12.整数转罗马数字

给定一个整数,将其转为罗马数字。输入确保在 1 到 3999 的范围内。

示例 1:

输入: 3
输出: "III"

示例 2:

输入: 4
输出: "IV"

示例 3:

输入: 9
输出: "IX"

示例 4:

输入: 58
输出: "LVIII"
解释: C = 100, L = 50, XXX = 30, III = 3.

示例 5:

输入: 1994
输出: "MCMXCIV"
解释: M = 1000, CM = 900, XC = 90, IV = 4.
class Solution {
    public String intToRoman(int num) {
       
        int[]values = {1000,900,500,400,100,90,50,40,10,9,5,4,1};
        String[]strs = {"M","CM","D","CD","C","XC","L","XL","X","IX","V","IV","I"};
        StringBuilder sb = new StringBuilder();
        for (int i=0;i<values.length;i++) {
            while (num >= values[i]) {
                num-=values[i];
                sb.append(strs[i]);
            }
        }
        return sb.toString();
    
    }
}

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转载自www.cnblogs.com/airycode/p/9764729.html