Multiply Strings 字符串相乘

http://www.cnblogs.com/TenosDoIt/p/3735309.html

https://blog.csdn.net/fly_yr/article/details/48055617

class Solution {
public:
    string multiply(string num1, string num2) {
        int len1 = num1.length();
        int len2 = num2.length();
        vector<int> res(len1+len2,0);
        int k = len1 + len2 - 2;          第一轮乘出来的结果只有len1+len2-1个,数组的index为0再减1
for(int i = 0;i < len1;i++){ for(int j = 0;j < len2;j++){ res[k - i - j] += (num1[i] - '0') * (num2[j] - '0');   num1[0]是原本数的最高位,这里做了个转换,把最低位的数放在了0位置 } } int carry = 0; for(int i = 0;i < len1 + len2;i++){ res[i] += carry; carry = res[i]/10; res[i] = res[i]%10; } int i = k + 1; while(res[i] == 0)          找寻第一个非0的位置 i--; if(i < 0) return "0"; string result; for(;i >= 0;i--) result.push_back(res[i] + '0'); return result; } };

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转载自www.cnblogs.com/ymjyqsx/p/9464311.html