hdu 2177(威佐夫博弈)

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2177

思路:模板题,暴力找出怎么取就行。

#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <cmath>
#include <cctype>
#include <iostream>
#include <algorithm>
#include <string>
#include <vector>
#include <queue>
#include <map>
#include <set>
#include <sstream>
#include<iomanip>
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
const ll inff = 0x3f3f3f3f3f3f3f3f;
#define FOR(i,a,b) for(int i(a);i<=(b);++i)
#define FOL(i,a,b) for(int i(a);i>=(b);--i)
#define REW(a,b) memset(a,b,sizeof(a))
#define inf int(0x3f3f3f3f)
#define si(a) scanf("%d",&a)
#define sl(a) scanf("%I64d",&a)
#define sd(a) scanf("%lf",&a)
#define ss(a) scanf("%s",a)
#define mod int(1e9+7)
#define lc (d<<1)
#define rc (d<<1|1)
#define P pair<int,int>
#define pi acos(-1)
void as(int n,int m)
{
    if(n<m) swap(n,m);
    int k=n-m;
    if((int)(k*(1+sqrt(5))/2.0)==m)
    {
        cout<<0<<endl;
        return;
    }
    else
    {
        cout<<1<<endl;
        int a,b;
        FOR(i,1,m)
        {
            a=n-i;
            b=m-i;
            k=a-b;
            if(b==(int)(k*(1+sqrt(5))/2.0))
            {
                cout<<b<<" "<<a<<endl;
                break;
            }
        }
        FOL(i,n-1,0)
        {
            b=i;
            a=m;
            if(a<b)  swap(a,b);
            k=a-b;
            if(b==(int)(k*(1+sqrt(5))/2.0))
            {
                cout<<b<<" "<<a<<endl;
            }
        }
    }
}
int main()
{
    cin.tie(0);
    int a,b;
    while(scanf("%d %d",&a,&b)!=EOF&&(a+b))
    {
        as(a,b);
    }
    return 0;
}

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转载自blog.csdn.net/qq_40858062/article/details/80160245