#include <stdio.h>
int gcd(int a, int b)
{
/*if(a<b){
int temp=a;
a=b;
b=temp;
}
if(b==0){
return 1;
}
int r=a%b;
if(r==0){
return b;
} else{
return gcd(b,r)
}*/
int r = a % b;
while (r)
{
a = b;
b = r;
r = a % b;
}
return b;
}
int main()
{
int a, b;
scanf("%d/%d", &a, &b);
int n = gcd(a, b);
printf("%d/%d", a / n, b / n);
}
基础编程题目集 7-24 约分最简分式 (15分)
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转载自blog.csdn.net/qq_44458489/article/details/105400274
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