#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<cmath>
using namespace std;
const int N=1000;
int main()
{
int a[N],n,i,num1,sum=0;
cin>>n;
memset(a,0,sizeof(a));
for(i=0;i<n;i++){
cin>>num1;
a[num1]++;
}
for(i=0;i<N;i++){
if(2*sum+a[i]==n){
cout<<i;
break;
}else{
sum+=a[i];
}
}
if(i==N){
cout<<"-1";
}
return 0;
}
CCF认证 201612-1:中间数(C++)
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转载自blog.csdn.net/weixin_44652687/article/details/104722118
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