顺序高斯消去法求解线性方程组(附上中间过程矩阵初等行变换)

别说了,先附上代码



#include <iostream>
#include<stdio.h>
using namespace std;
void print(double **a,int n)
{
    int i,j;
    for(i=0;i<n;i++)
    {
        for(j=0;j<n+1;j++)
        {
            printf("%.4lf ",a[i][j]);
        }
        cout<<endl;
    }

}
void shunxu_G_S(double **a,int n)
{
    /*先做消去*/
    int k,i,j;
    int c[n];
    for(k=0;k<n-1;k++)
    {
        for (i = k + 1; i < n; i++)
            c[i] = a[i][k] / a[k][k];

        for(i=k+1;i<n;i++)
        {
            for(j=0;j<n+1;j++)
            {
                a[i][j]=a[i][j]-c[i]*a[k][j];
            }
        }
        print(a,n);
        cout<<endl;
    }
    /*在做回代*/
    double x[n];
    x[n-1]=a[n-1][n]/a[n-1][n-1];
    for (i = n - 2; i >= 0; i--)
    {
        double sum = 0;
        for (j = i + 1; j < n; j++)
        {
            sum += a[i][j] * x[j];
        }
        x[i] = (a[i][n] - sum) / a[i][i];
    }
    cout<<"方程组的解为"<<endl;
    for(i=0;i<n;i++)
    {
        printf("%.4lf ",x[i]);
    }


}

int main()
{
     double **a;
    int n;
    cout << "输入系数矩阵的阶数n:" << endl;
    cin >> n;
    cout << "依次输入增广矩阵的每一个元素A[i][j]:" << endl;
    a = new double *[n];
    for (int i = 0; i < n; i++)
        a[i] = new double[n+1];
    for (int i = 0; i < n; i++)
        for (int j = 0; j < n+1; j++)
            {cin >> a[i][j];}
    cout<<"中间过程的矩阵初等行变化: "<<endl;
    shunxu_G_S(a,n);


    return 0;


运行结果如下:在这里插入图片描述

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转载自blog.csdn.net/qq_45695724/article/details/104735396