A + B Problem II
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 413635 Accepted Submission(s): 80168
Problem Description
I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.
Input
The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.
Output
For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.
Sample Input
2 1 2 112233445566778899 998877665544332211
Sample Output
Case 1: 1 + 2 = 3 Case 2: 112233445566778899 + 998877665544332211 = 1111111111111111110
刷ACM的题,大数用C语言写,只能用数组模拟,很麻烦,现在大二了,学习了java,今天做的第一个大数加法题,绝对比C语言要简单的多了。
import java.math.*; import java.util.*; import java.*; public class Main{ public static void main(String[] args){ Scanner scanner = new Scanner(System.in); int n; n = scanner.nextInt(); for (int i=1;i<=n;i++){ System.out.println("Case " + i + ":"); BigInteger a,b,c; a = scanner.nextBigInteger(); b = scanner.nextBigInteger(); c = a.add(b); System.out.println(a.toString() + " + " + b.toString() + " = " + c.toString()); if(i!=n){ System.out.println(); } } } }