hdoj6441（勾股数）（模板 重要）

a^n+b^n=c^n 给出a与n，问是否可以求出b,c

费马大定理可知n>2时无解，n=1时无需多言,n=2时用勾股数定理求得

#include <cstdio>
typedef long long ll;
int main() {
	int T;
	scanf("%d", &T);
	
	while (T--) {
		ll n, a, b, c;
		scanf("%lld%lld", &n, &a);
		if (n == 1) {
			printf("%lld %lld\n", 1, 1+a);
		}
		else if (n == 2) {
			if (a % 2 == 1) {
				ll tmp = (a-1)/2;
				b = 2*tmp*tmp+2*tmp;
				c = b+1;
				printf("%lld %lld\n", b, c);
			}
			else {
				ll tmp = a/2 - 1;
				b = tmp*tmp + 2*tmp;
				c = b + 2;
				printf("%lld %lld\n", b, c);
			}
		}
		else printf("-1 -1 \n");
	}
	return 0;
}