poj3320 Jessica's Reading Problem 尺取法

http://poj.org/problem?id=3320

#include <iostream>
#include <algorithm>
#include <cstdio> 
#include <cstring>
#include <set>
#include <map>
using namespace std;
const int maxn=100005;
int p,a[maxn];
void solve(){
	set<int>all;//计算无重复的知识点个数 
	for(int i=0;i<p;i++){
		all.insert(a[i]);
	}
	int n=all.size();
	int s=0,t=0,num=0;
	map<int,int>count; //知识点->出现次数的映射
	int res=p;
	for(;;){
		while(t<p&&num<n){
			if(count[a[t++]]++==0){//出现新的知识点 
				num++;
			}
		}
		if(num<n) break;
		res=min(res,t-s);
		if(--count[a[s++]]==0){//某个知识点的出现次数为0了 
			num--;
		}
	} 
	printf("%d\n",res);
}
int main(){
	while(scanf("%d",&p)!=EOF){//用cin超时
		for(int i=0;i<p;i++){
			scanf("%d",&a[i]);
		}
		solve();
	}
	return 0;
}

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转载自blog.csdn.net/skykone1/article/details/86911258