二分求LIS


#include <bits/stdc++.h>
#include <iostream>
#include <cstring>
#include <stdio.h>

using namespace std;

int L[10];
int Length = -1;
int N;
int num;

int BinFind(int Len[], int &X)      //返回第一个比X大的下标
{
    int L = 0;
    int R = Length;

    while(L <= R)
    {
        int Mid = (L+R)/2;

        if(X < Len[Mid])
            R = Mid - 1;
        else if(X > Len[Mid])
            L = Mid + 1;
        else
            return Mid;
    }
    return L;
}

int main(int argc, char *argv[])
{

    freopen("G:\\data.txt", "r", stdin);

    cin >> N;

    for(int i = 0; i < N; i++)
    {
        cin >> num;

        int cc = BinFind(L, num);

        if(cc > Length)
            L[++Length] = num;
        else
            L[cc] = num;
    }

    cout << Length << endl;

    return 0;
}
















猜你喜欢

转载自blog.csdn.net/canhelove/article/details/88390643