数位dp模板_不要62

#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<queue>
#include<cmath>
#include<cstdlib>
#include<ctime>
using namespace std;
typedef long long ll;
const int inf=0x3f3f3f3f;
inline int read(){
	char ch=' ';int f=1;int x=0;
	while(ch<'0'||ch>'9'){if(ch=='-') f=-1;ch=getchar();}
	while(ch>='0'&&ch<='9')x=x*10+ch-'0',ch=getchar();
	return x*f;
}
int dp[20][2];
int a[20];
int dfs(int pos,int pre,int state,bool limit)
{
	if(pos==0) return 1.;
	if(!limit&&dp[pos][state]!=-1) return dp[pos][state];
	int up=limit?a[pos]:9;
	int ans=0;
	for(int i=0;i<=up;i++)
	{
		if(i==4) continue;
		if(pre==6&&i==2) continue;
		ans+=dfs(pos-1,i,i==6,limit&&i==a[pos]);
	}
	if(!limit) dp[pos][state]=ans;
	return ans;
}
int solve(int x)
{
	int pos=0;
	while(x)
	{
		a[++pos]=x%10;
		x/=10;
	}
	return dfs(pos,0,0,1);
}
int main()
{
	int l,r;
	while(scanf("%d%d",&l,&r)!=EOF)
	{
		if(l==0&&r==0)
		{
			break;
		}
		memset(dp,-1,sizeof(dp));
		printf("%d\n",solve(r)-solve(l-1));
	}
	return 0;
}


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转载自blog.csdn.net/qq_42110318/article/details/83830604