数值分析复习

Hermite插值

α i ( x ) = [ 1 + 2 ( x i x ) k = 0 , k i n 1 x i x k ] l i 2 ( x ) \alpha_i(x)=[1+2(x_i- x)\sum_{k=0,k\ne i}^{n}\frac{1}{x_i-x_k}]l_i^2(x)
β i ( x ) = ( x x i ) l i 2 ( x ) \beta_i(x)=(x-x_i)l_i^2(x)
当n=1时
H 3 ( x ) = f ( x 0 ) [ 1 + 2 ( x 0 x ) x 0 x 1 ] ( x x 1 x 0 x 1 ) 2 + f ( x 1 ) [ 1 + 2 ( x 1 x ) x 1 x 0 ] ( x x 0 x 1 x 0 ) 2 + f ( x 0 ) ( x x 0 ) ( x x 1 x 0 x 1 ) 2 + f ( x 1 ) ( x x 1 ) ( x x 0 x 1 x 0 ) 2 H_3(x)=f(x_0)[1+2\frac{(x_0-x)}{x_0-x_1}](\frac{x-x_1}{x_0-x_1})^2+ f(x_1)[1+2\frac{(x_1-x)}{x_1-x_0}](\frac{x-x_0}{x_1-x_0})^2+ f'(x_0)(x-x_0)(\frac{x-x_1}{x_0-x_1})^2+ f'(x_1)(x-x_1)(\frac{x-x_0}{x_1-x_0})^2

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转载自blog.csdn.net/guojunxiu/article/details/84982788
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