Code:
#include<bits/stdc++.h>
using namespace std;
const int MAX = 2000;
int n, m, x, y;
int a[MAX + 5], lg[MAX + 5], maxn[MAX + 5][MAX + 5];
void solve(int *x) {
for (int i = 1; i <= n; i++) {
lg[i] = lg[i - 1];
if (1 << lg[i - 1] + 1 == i) lg[i]++;
//cout << "lg[" << i << "]:" << lg[i] << endl;
}
for (int j = 1; j <= lg[n]; j++)
{
for (int i = 1; i + (1 << j) - 1 <= n; i++)
{
maxn[i][j] = max(maxn[i][j - 1], maxn[i + 1 << (j - 1)][j - 1]);
}
}
}
int askm(int l, int r) {
int k = lg[r - l + 1];
return max(maxn[l][k], maxn[r - (1 << k) + 1][k]);
}
int main() {
cin >> n >> m;
for (int i = 1; i <= n; i++) {
cin >> a[i];
maxn[i][0] = a[i];
}
solve(a);
//for (int i = 1; i <= n; ++i)
//{
// for (int j = 0; j <= n; ++j)
// {
// cout << "max[" << i << "][" << j << "]:" << maxn[i][j] << " ";
// }
// cout << endl;
//}
for (int i = 1; i <= m; i++) {
cin >> x >> y;
cout << askm(x, y) << endl;
}
return 0;
}
Analysis:
竖着读maxn数组:
Code2:
#include<algorithm>
#include<iostream>
#include<cstring>
#include<cstdio>
#include<cmath>
using namespace std;
int a[100001],f[100001][20];
inline int read(){
int x=0,f=1;
char c=getchar();
for(;!isdigit(c);c=getchar())
if(c=='-')
f=-1;
for(;isdigit(c);c=getchar())
x=x*10+c-'0';
return x*f;
}
void RMQ(int N){
for(int j=1;j<=20;j++)
for(int i=1;i<=N;i++)
if(i+(1<<j)-1<=N)
f[i][j]=max(f[i][j-1],f[i+(1<<(j-1))][j-1]);
}
int main(){
int N=read(),M=read();
for(int i=1;i<=N;i++) a[i]=read();
for(int i=1;i<=N;i++) f[i][0]=a[i];
RMQ(N);
while(M--){
int i=read(),j=read();
int k=(int)(log((double)(j-i+1))/log(2.0));
printf("%d\n",max(f[i][k],f[j-(1<<k)+1][k]));
}
return 0;
}