版权声明:本文为博主原创文章,未经博主允许不得转载 https://blog.csdn.net/qit1314/article/details/83870113
两个不同点A,B确定一条直线,AB相同返回的值全0
- 直线方程:Ax+By+c=0
- A = y2 - y1;
- B = x1 - x2;
- C = -Ax1 - By1 = x2y1 - x1y2;
证明之后补上;
Line LineMake(Point A, Point B)
{
Line l;
l.A = B.y - A.y;
l.B = A.x - B.x;
l.C = B.x * A.y - A.x * B.y;
return l;
}