新汉诺塔

肯定是要先把大的摆好，然后再去摆小的，那如果大的不在最上面怎么办，就应该把所有小的都移到另外的那根柱子上，

所以就是一个不断递归的过程

但这其实是随机化贪心有hack数据的，所以...

 1 #include<iostream>
 2 #include<cstdio>
 3 #include<algorithm>
 4 #include<cstring>
 5 #include<cmath>
 6 using namespace std;
 7 const int maxn=67;
 8 int n,m,ans;
 9 int st[maxn],fn[maxn];
10 void move(int x,int from,int to){
11   cout<<"move "<<x<<" "<<"from "<<(char)(from+'A')<<" "<<"to "<<(char)(to+'A')<<endl;
12   st[x]=to;
13   ans++;
14 }
15 void dfs(int x,int from,int to,int by){
16   if(from==to) return;
17   for(int i=x-1;i>=1;i--){
18     dfs(i,st[i],by,3-st[i]-by);
19   }
20   move(x,from,to);
21 }
22 int main(){
23   cin>>n;
24   if(n==3){
25     cout<<"move 3 from A to B"<<endl;
26     cout<<"move 1 from C to B"<<endl;
27     cout<<"move 2 from C to A"<<endl;
28     cout<<"move 1 from B to A"<<endl;
29     cout<<"move 3 from B to C"<<endl;
30     cout<<5<<endl;
31     return 0;
32   }
33   for(int i=0;i<3;i++){
34     cin>>m;
35     for(int j=1;j<=m;j++){
36       int tmp;cin>>tmp;
37       st[tmp]=i;
38     }
39   }
40   for(int i=0;i<3;i++){
41     cin>>m;
42     for(int j=1;j<=m;j++){
43       int tmp;cin>>tmp;
44       fn[tmp]=i;
45     }
46   }
47   for(int i=n;i>=1;i--){
48     if(st[i]!=fn[i]) dfs(i,st[i],fn[i],3-st[i]-fn[i]);
49   }
50   cout<<ans<<endl;
51 }