C语言写出三子棋其实难度不能算很高，难的是你能在里面下得和电脑难分难解；基于这个目的
我写出了这个可选难度的三子棋游戏.各位了解一下.....
头文件game.h：
#ifndef __GAME_H__
#define __GAME_H__
#include<stdio.h>
#include<stdlib.h>
#include<windows.h>
#include<time.h>
#include<string.h>
#define ROW 3
#define LIN 3
void game();
void menu();
void initboard(char arr[ROW][LIN], int row, int lin);
void checkboard(char arr[ROW][LIN], int row, int lin);
void player_go(char arr[ROW][LIN], int row, int lin);
void pc_go(char arr[ROW][LIN], int row, int lin, int nan);
int is_full(char arr[ROW][LIN], int row, int lin);
char is_win(char arr[ROW][LIN], int row, int lin);
#endif //game.h然后是测试源码
test.c
#include "game.h"
int main()
{
int input=0;
do{
menu();
printf("请选择： \n");
scanf_s("%d", &input);
switch (input)
{
case 1:
game(); break;
case 0:
exit(0); break;
default:
printf("请重新输入\n"); break;
}
} while (1);
}最后就是游戏源文件
game.c
#include "game.h"
void menu()
{
printf("***********************\n");
printf("***** 1.开始游戏 *****\n");
printf("***** 0.退出游戏 *****\n");
printf("***********************\n");
}
void initboard(char arr[][LIN], int row,int lin)//初始化棋盘
{
memset(arr, ' ', sizeof(arr[0][0])*lin*row);
}
void checkboard(char arr[][LIN], int row, int lin)//打印棋盘
{
int i = 0;
int j = 0;
for (i=0; i<row; i++)
{
for(j=0; j<lin; j++)
{
printf(" %c ", arr[i][j]);
if(j < lin-1)
printf("|");
else
printf("\n");
}
if (i < row-1)
{
for(j=0; j<lin; j++)
{
printf("---");
if(j < lin-1)
printf("|");
else
printf("\n");
}
}
}
printf("\n");
}
void player_go(char arr[][LIN], int row, int lin)//玩家走
{
int i, j, input;
while(1)
{
printf("请你落子(1-9): \n");
//scanf_s("%d %d", &i, &j);
scanf("%d",&input);
i = (input+2)/3;
j = (input%3 == 0)? 3:input%3;
if (i >=1 && i <= row&&j >=1 && j <= lin)
{
if (arr[i - 1][j - 1] ==' ')
{
arr[i - 1][j - 1] = 'X';
break;
}
else {
printf("已经有子了！\n");
}
}
else {
printf("错误落子，请重新落子\n");
}
}
//system("cls");
}
void pc_go(char arr[][LIN], int row, int lin, int nan)//电脑走
{
int i, j, count;
int sig = 0;
int i2 = 6, j2 = 6;
int m = 0;
int n = 0;
count = 0;
printf("电脑思考中");
Sleep(200);
printf(".");
Sleep(200);
printf(".");
Sleep(200);
printf(".\n电脑落子：\n");
switch(nan)
{
//难度1
case 1:
do
{
i = rand() % row;
j = rand() % lin;
if (arr[i][j] == ' ')
{
arr[i][j] = 'O';
break;
}
} while (1);
break;
//难度二
case 2:
count = 1;
if(arr[1][1] == ' ')
{
arr[1][1] = 'O';
goto done2;
}
nan2:
for(i=0; i<row; i++)
{
n = 0;
m = 0;
for(j=0; j<lin; j++)
{
m += arr[i][j];
n += arr[j][i];
}
if(m == 'O'*2 + ' ')
{
for(j=0; j<lin; j++)
{
if(arr[i][j] == ' ')
{
arr[i][j] = 'O';
goto done2;
}
}
}
if(m == 'X'*2 + ' ')
{
sig++;
i2 = i;
}
//行
if(n == 'O'*2 + ' ')
{
for(j=0; j<row; j++)
{
if(arr[j][i] == ' ')
{
arr[j][i] = 'O';
goto done2;
}
}
}
if(n == 'X'*2 + ' ')
{
sig++;
j2 = i;
}
}
if(sig)
{
if(i2 < row)
{
for(j=0; j<lin; j++)
{
if(arr[i2][j] == ' ')
{
arr[i2][j] = 'O';
goto done2;
}
}
}
else
{
for(j=0; j<row; j++)
{
if(arr[j][j2] == ' ')
{
arr[j][j2] = 'O';
goto done2;
}
}
}
}
//列
if(arr[0][0]+arr[1][1]+arr[2][2] == 'O'*2 + ' '||arr[0][0]+arr[1][1]+arr[2][2] == 'X'*2 + ' ')
{
for(i=0; i<lin; i++)
{
if(arr[i][i] == ' ')
{
arr[i][i] = 'O';
goto done2;
}
}
}
if(arr[2][0]+arr[1][1]+arr[0][2] == 'O'*2 + ' '||arr[2][0]+arr[1][1]+arr[0][2] == 'X'*2 + ' ')
{
for(j=0; j<row; j++)
{
if(arr[row-j-1][j] == ' ')
{
arr[row-j-1][j] = 'O';
goto done2;
}
}
}//斜
do
{
i = rand() % row;
j = rand() % lin;
if (arr[i][j] == ' ')
{
arr[i][j] = 'O';
goto done2;
}
} while (1);
done2:
break;
//难度三
case 3:
if(arr[1][1] == ' ')
{
arr[1][1] = 'O';
goto done3;
}
else
{
for(i=0; i<row; i++)
{
for(j=0; j<lin; j++)
{
count += arr[i][j];
}
}
if((count == 'X'+ 8*' ') && arr[1][1] == 'X')
{
arr[0][0] = 'O';
goto done3;
}
if((count == 'X'*2 + 'O'*1 + ' '*6) && arr[2][2] == 'X' && arr[1][1] == 'X')
{
arr[0][2] = 'O';
goto done3;
}
else if((count == 'X'*2 + 'O'*1 + ' '*6) && arr[1][1] == 'O')
{
arr[0][1] = 'O';
goto done3;
}
goto nan2;
}
done3:
break;
}
//system("cls");
}
int is_full(char arr[][LIN], int row, int lin)//判断棋盘是否为满
{
int i=0, j=0;
for (i=0; i<row; i++)
{
for (j=0; j<lin; j++)
{
if (arr[i][j] == ' ')
return 0;
}
}
return 1;
}
char is_win(char arr[][LIN], int row, int lin)//判断输赢
{
int i = 0, j = 0;
for (i=0; i<row; i++)
{
if ((arr[i][0] == arr[i][1])&&( arr[i][1] == arr[i][2] )&& arr[i][1] != ' ') //判断行
{
return arr[i][1];
}
}
for (j=0; j<lin; j++) //判断列
{
if ((arr[0][j] == arr[1][j] ) && ( arr[1][j] == arr[2][j]) && arr[1][j] != ' ')
{
return arr[1][j];
}
}
if ((arr[0][0] == arr[1][1] ) && (arr[1][1] == arr[2][2]) && arr[1][1] != ' ') //判断斜列
{
return arr[1][1];
}
else if( (arr[0][2] == arr[1][1]) && ( arr[1][1] == arr[2][0]) && arr[1][1] != ' ')
{
return arr[1][1];
}
else if (is_full(arr,row,lin))
{
return 'f';
}
else return ' ';
}
void game()
{
int input;
char ret;
char arr[ROW][LIN] ;
while(1)
{
system("cls");
initboard(arr, ROW, LIN);
printf("**************************************\n");
printf("* *\n");
printf("*请选择难度：1.简单 2.困难 3.大师*\n");
printf("* *\n");
printf("**************************************\n");
scanf("%d",&input);
if (input>3 || input<1)
{
printf("输入错误！重新输入！");
Sleep(500);
}
else break;
}
system("cls");
printf("\n");
checkboard(arr, ROW, LIN);
srand((unsigned int)time(NULL));
do
{
player_go(arr, ROW, LIN);
//system("cls");
checkboard(arr, ROW, LIN);
ret = is_win(arr, ROW, LIN);
if (ret != ' ')
{
break;
}
Sleep(1000);
system("cls");
pc_go(arr, ROW, LIN, input);
checkboard(arr, ROW, LIN);
ret = is_win(arr, ROW, LIN);
if (ret != ' ')
{
break;
}
} while (1);
if (ret == 'X')
{
printf("你赢了！\n");
}
else if (ret == 'O')
{
printf("你输了！\n");
}
else if (ret == 'f')
{
printf("平局！\n");
}
}