pat 甲级 1036 Boys vs Girls

第二次提交通过
因为忘了不存在的不仅要在差值的地方输出NA，还要输出 Absent

还是简单滴

#include <cstdio>
#include <iostream>
#include <algorithm>

using namespace std;

int n;
struct student{
    string name;
    char g;
    string id;
    int grade;
};

student stu[11000];

bool mygrade(student a, student b){
    return a.grade < b.grade;
}

int main(){

    scanf("%d",&n);
    int k=0;
    for(int i=0; i<n; i++){
        string a,b;
        char c;
        int d;
        cin >> a >> c >> b >> d;
        stu[i].name = a;
        stu[i].g = c;
        stu[i].id = b;
        stu[i].grade = d; 
        k++;                
    }
    sort(stu,stu+k,mygrade);
    int ma = -1, mi = -1;
    for(int i=k-1; i>=0; i--){
        if(stu[i].g=='F'){
            cout << stu[i].name << " " << stu[i].id << endl;
            ma = stu[i].grade;
            break;
        }
    }
    if(ma == -1) printf("Absent\n");
    for(int i=0; i<k; i++){
        if(stu[i].g=='M'){
            cout << stu[i].name << " " << stu[i].id << endl;
            mi = stu[i].grade;
            break;
        }
    }
    if(mi == -1) printf("Absent\n");
    if(ma != -1 && mi != -1) printf("%d",ma - mi);
    else printf("NA"); 

    return 0;
}

晚上了，挑个好写的过了