目录
1036 Boys vs Girls (25分)
题目原文
This time you are asked to tell the difference between the lowest grade of all the male students and the highest grade of all the female students.
Input Specification:
Each input file contains one test case. Each case contains a positive integer N, followed by N lines of student information. Each line contains a student's name
, gender
, ID
and grade
, separated by a space, where name
and ID
are strings of no more than 10 characters with no space, gender
is either F
(female) or M
(male), and grade
is an integer between 0 and 100. It is guaranteed that all the grades are distinct.
Output Specification:
For each test case, output in 3 lines. The first line gives the name and ID of the female student with the highest grade, and the second line gives that of the male student with the lowest grade. The third line gives the difference gradeF−gradeM. If one such kind of student is missing, output Absent
in the corresponding line, and output NA
in the third line instead.
Sample Input 1:
3
Joe M Math990112 89
Mike M CS991301 100
Mary F EE990830 95
Sample Output 1:
Mary EE990830
Joe Math990112
6
Sample Input 2:
1
Jean M AA980920 60
Sample Output 2:
Absent
Jean AA980920
NA
生词
guaranteed 保证
distinct 不同的
题目大意
在M个男生和女生中,找出最低成绩的男生,最高成绩的女生,并且输出他们的分数差
没有就输出Absent ,分数差哪里输出NA
代码如下
#include<iostream>
#include<cstdio>
#include<cmath>
using namespace std;
struct Students {
char Name[11];
char ID[11];
char Sex;
int Gender;
};
int main(void) {
struct Students BoyGirl[10000];
int K, MaxGender=-1, MaxID=-1, MinGender=101, MinID=-1; //给-1和101是为了让Max和Min都一定可以被取到
scanf("%d", &K);
for (int i = 0; i < K; i++) {
scanf("%s %c %s %d", &BoyGirl[i].Name,
&BoyGirl[i].Sex, &BoyGirl[i].ID,
&BoyGirl[i].Gender);
if (BoyGirl[i].Sex == 'M') {
if (BoyGirl[i].Gender < MinGender) {
MinGender = BoyGirl[i].Gender;
MinID = i;
}
} //判断男孩
if (BoyGirl[i].Sex == 'F') {
if (BoyGirl[i].Gender > MaxGender) {
MaxGender = BoyGirl[i].Gender;
MaxID = i;
}
} //判断女孩
}
if (MaxID != -1)
printf("%s %s\n", BoyGirl[MaxID].Name, BoyGirl[MaxID].ID);
else
printf("Absent\n");
if (MinID != -1)
printf("%s %s\n", BoyGirl[MinID].Name, BoyGirl[MinID].ID);
else
printf("Absent\n");
if (MaxID != -1 && MinID != -1) {
printf("%d", abs(MaxGender - MinGender));
}
else
printf("NA");
return 0;
}