数据清洗之 日期格式数据处理

日期格式数据处理

  • Pandas中使用to_datetime()方法将文本格式转换为日期格式
  • dataframe数据类型如果为datetime64,可以使用dt方法取出年月日等
  • 对于时间差数据,可以使用timedelta函数将其转换为指定时间单位的数值
  • 时间差数据,可以使用dt方法访问其常用属性
import pandas as pd
import numpy as np
import os
os.getcwd()
'D:\\Jupyter\\notebook\\Python数据清洗实战\\数据清洗之数据转换'
os.chdir('D:\\Jupyter\\notebook\\Python数据清洗实战\\数据')
df = pd.read_csv('baby_trade_history.csv', encoding='utf-8', dtype={'user_id':str})
df.head(5)
user_id auction_id cat_id cat1 property buy_mount day
0 786295544 41098319944 50014866 50022520 21458:86755362;13023209:3593274;10984217:21985... 2 20140919
1 532110457 17916191097 50011993 28 21458:11399317;1628862:3251296;21475:137325;16... 1 20131011
2 249013725 21896936223 50012461 50014815 21458:30992;1628665:92012;1628665:3233938;1628... 1 20131011
3 917056007 12515996043 50018831 50014815 21458:15841995;21956:3494076;27000458:59723383... 2 20141023
4 444069173 20487688075 50013636 50008168 21458:30992;13658074:3323064;1628665:3233941;1... 1 20141103
df.info()
<class 'pandas.core.frame.DataFrame'>
RangeIndex: 29971 entries, 0 to 29970
Data columns (total 7 columns):
user_id       29971 non-null object
auction_id    29971 non-null int64
cat_id        29971 non-null int64
cat1          29971 non-null int64
property      29827 non-null object
buy_mount     29971 non-null int64
day           29971 non-null int64
dtypes: int64(5), object(2)
memory usage: 1.6+ MB
df['buy_date'] = pd.to_datetime(df['day'], format='%Y%m%d', errors='coerce')
df.info()
<class 'pandas.core.frame.DataFrame'>
RangeIndex: 29971 entries, 0 to 29970
Data columns (total 8 columns):
user_id       29971 non-null object
auction_id    29971 non-null int64
cat_id        29971 non-null int64
cat1          29971 non-null int64
property      29827 non-null object
buy_mount     29971 non-null int64
day           29971 non-null int64
buy_date      29971 non-null datetime64[ns]
dtypes: datetime64[ns](1), int64(5), object(2)
memory usage: 1.8+ MB
df.head(5)
user_id auction_id cat_id cat1 property buy_mount day buy_date
0 786295544 41098319944 50014866 50022520 21458:86755362;13023209:3593274;10984217:21985... 2 20140919 2014-09-19
1 532110457 17916191097 50011993 28 21458:11399317;1628862:3251296;21475:137325;16... 1 20131011 2013-10-11
2 249013725 21896936223 50012461 50014815 21458:30992;1628665:92012;1628665:3233938;1628... 1 20131011 2013-10-11
3 917056007 12515996043 50018831 50014815 21458:15841995;21956:3494076;27000458:59723383... 2 20141023 2014-10-23
4 444069173 20487688075 50013636 50008168 21458:30992;13658074:3323064;1628665:3233941;1... 1 20141103 2014-11-03
# 使用dt方法提取属性
# df['buy_date'].dt.year  # 提取年
# df['buy_date'].dt.month  # 提取月
# df['buy_date'].dt.day  # 提取天
df['diff_day'] = pd.datetime.now() - df['buy_date']  # 时间差格式
df.head(5)
user_id auction_id cat_id cat1 property buy_mount day buy_date diff_day
0 786295544 41098319944 50014866 50022520 21458:86755362;13023209:3593274;10984217:21985... 2 20140919 2014-09-19 2034 days 22:32:35.614788
1 532110457 17916191097 50011993 28 21458:11399317;1628862:3251296;21475:137325;16... 1 20131011 2013-10-11 2377 days 22:32:35.614788
2 249013725 21896936223 50012461 50014815 21458:30992;1628665:92012;1628665:3233938;1628... 1 20131011 2013-10-11 2377 days 22:32:35.614788
3 917056007 12515996043 50018831 50014815 21458:15841995;21956:3494076;27000458:59723383... 2 20141023 2014-10-23 2000 days 22:32:35.614788
4 444069173 20487688075 50013636 50008168 21458:30992;13658074:3323064;1628665:3233941;1... 1 20141103 2014-11-03 1989 days 22:32:35.614788
df.dtypes
user_id                object
auction_id              int64
cat_id                  int64
cat1                    int64
property               object
buy_mount               int64
day                     int64
buy_date       datetime64[ns]
diff_day      timedelta64[ns]
dtype: object
# 使用dt方法提取属性
# df['diff_day'].dt.days  # 提取天数
# df['diff_day'].dt.seconds  # 提取秒
# df['diff_day'].dt.microseconds  # 提取纳秒
# 将时间差转换为规定的格式
df['时间差'] = df['diff_day']/pd.Timedelta('1 D')  # 转换为天数
df['时间差'].head(5)
0    2034.939301
1    2377.939301
2    2377.939301
3    2000.939301
4    1989.939301
Name: 时间差, dtype: float64
df['时间差'] = df['diff_day']/pd.Timedelta('1 H')  # 转换为小时
df['时间差'].head(5)
0    48838.543226
1    57070.543226
2    57070.543226
3    48022.543226
4    47758.543226
Name: 时间差, dtype: float64
df['时间差'] = df['diff_day']/pd.Timedelta('1 M')  # 转换为分钟数
df['时间差'].head(5)
0    2.930313e+06
1    3.424233e+06
2    3.424233e+06
3    2.881353e+06
4    2.865513e+06
Name: 时间差, dtype: float64
# 将科学计数转换为小数
df['时间差'].head(5).round(decimals=3)
0    2930312.594
1    3424232.594
2    3424232.594
3    2881352.594
4    2865512.594
Name: 时间差, dtype: float64
# D: 天  M: 月  Y: 年
# 转换为天数
df['diff_day'].astype('timedelta64[D]').head(5)
0    2034.0
1    2377.0
2    2377.0
3    2000.0
4    1989.0
Name: diff_day, dtype: float64
# 转换为月数
df['diff_day'].astype('timedelta64[M]').head(5)
0    66.0
1    78.0
2    78.0
3    65.0
4    65.0
Name: diff_day, dtype: float64
# 转换为年数
df['diff_day'].astype('timedelta64[Y]').head(5)
0    5.0
1    6.0
2    6.0
3    5.0
4    5.0
Name: diff_day, dtype: float64
# 转换为小时
# 还可转换为分钟、秒等等
df['diff_day'].astype('timedelta64[h]').head(5)
0    48838.0
1    57070.0
2    57070.0
3    48022.0
4    47758.0
Name: diff_day, dtype: float64
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