[leetcode]41. First Missing Positive

链接:https://leetcode.com/problems/first-missing-positive/description/

Given an unsorted integer array, find the smallest missing positive integer.

Example 1:

Input: [1,2,0]
Output: 3

Example 2:

Input: [3,4,-1,1]
Output: 2

Example 3:

Input: [7,8,9,11,12]
Output: 1

思路:交换数组元素,使得数组中第i位存放数值(i+1)。最后遍历数组,寻找第一个不符合此要求的元素,返回其下标。整个过程需要遍历两次数组,复杂度为O(n)

下图以题目中给出的第二个例子为例,讲解操作过程。


class Solution {
public:
    int firstMissingPositive(vector<int>& nums) {
        int i=0;
        int n=nums.size();
        while(i<n)
        {
            if(nums[i]!=(i+1) && nums[i]>=1 && nums[i]<=n && nums[nums[i]-1]!=nums[i])
                swap(nums[i],nums[nums[i]-1]);
            else
                i++;
        }
        for(i=0;i<n;i++)
            if(nums[i]!=(i+1))
                return i+1;
        return n+1;
    }
};


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转载自blog.csdn.net/xiaocong1990/article/details/80300827