POJ 1811 Prime Test

题目描述

Given a big integer number, you are required to find out whether it's a prime number.

Input

The first line contains the number of test cases T (1 <= T <= 20 ), then the following T lines each contains an integer number N (2 <= N < ).

Output

For each test case, if N is a prime number, output a line containing the word "Prime", otherwise, output a line containing the smallest prime factor of N.

Sample Input

2
5
10

Sample Output

Prime
2

题目大意

给你一个大数，要你判断他是不是素数，如果不是将它最小的素因子求出。

解题报告

1：直接套模板。

代码：

#include<iostream>
#include<cstdio>
#include<cstdlib>
using namespace std;
typedef long long LL;
#define maxn 10000
LL factor[maxn];
int tot;
const int S=20;

LL muti_mod(LL a,LL b,LL c){
    a%=c;
    b%=c;
    LL ret=0;
    while (b){
        if (b&1){
            ret+=a;
            if (ret>=c) ret-=c;
        }
        a<<=1;
        if (a>=c) a-=c;
        b>>=1;
    }
    return ret;
}

LL pow_mod(LL x,LL n,LL mod){
    if (n==1) return x%mod;
    int bit[90],k=0;
    while (n){
        bit[k++]=n&1;
        n>>=1;
    }
    LL ret=1;
    for (k=k-1;k>=0;k--){
        ret=muti_mod(ret,ret,mod);
        if (bit[k]==1) ret=muti_mod(ret,x,mod);
    }
    return ret;
}

bool check(LL a,LL n,LL x,LL t){
    LL ret=pow_mod(a,x,n),last=ret;
    for (int i=1;i<=t;i++){
        ret=muti_mod(ret,ret,n);
        if (ret==1 && last!=1 && last!=n-1) return 1;
        last=ret;
    }
    if (ret!=1) return 1;
    return 0;
}



bool Miller_Rabin(LL n){//判断素数  返回0代表素数
    LL x=n-1,t=0;
    while ((x&1)==0) x>>=1,t++;
    bool flag=1;
    if (t>=1 && (x&1)==1){
        for (int k=0;k<S;k++){
            LL a=rand()%(n-1)+1;
            if (check(a,n,x,t)) {flag=1;break;}
            flag=0;
        }
    }
    if (!flag || n==2) return 0;
    return 1;
}

LL gcd(LL a,LL b){
    if (a==0) return 1;
    if (a<0) return gcd(-a,b);
    while (b){
        LL t=a%b; a=b; b=t;
    }
    return a;
}

LL Pollard_rho(LL x,LL c){
    LL i=1,x0=rand()%x,y=x0,k=2;
    while (1){
        i++;
        x0=(muti_mod(x0,x0,x)+c)%x;
        LL d=gcd(y-x0,x);
        if (d!=1 && d!=x){
            return d;
        }
        if (y==x0) return x;
        if (i==k){
            y=x0;
            k+=k;
        }
    }
}


void findfac(LL n){           //递归进行质因数分解N
    if (!Miller_Rabin(n)){
        factor[tot++] = n;
        return;
    }
    LL p=n;
    while (p>=n) p=Pollard_rho(p,rand() % (n-1) +1);
    findfac(p);
    findfac(n/p);
}


int main(){
    int t;
    LL n;
    scanf("%lld", &t);
    while(t--){
        tot = 0;
        scanf("%lld", &n);
        if(!Miller_Rabin(n)){
            printf("Prime\n");
            continue;
        }
        findfac(n);
        LL ans = n;
        for(int i=0; i<tot; ++i)
            ans = min(ans, factor[i]);
        printf("%lld\n", ans);
    }
    return 0;
}