LeetCode-11. Container With Most Water

Description

Given n non-negative integers a1, a2, ..., an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find 
two lines, which together with x-axis forms a container, such that the container contains 
the most water.

Note

You may not slant the container and n is at least 2.

Solution 1(C++)

class Solution {
public:
    int maxArea(vector<int>& height) {
        int water = 0;
        int i = 0, j = height.size() - 1;
        while (i < j) {
            int h = min(height[i], height[j]);
            water = max(water, (j - i) * h);
            while (height[i] <= h && i < j) i++;
            while (height[j] <= h && i < j) j--;
        }
        return water;
    }
};

算法分析

这道题真没想到走的是实用主义。是我想太多了。

简单就好。积累积累吧。

程序分析

注意两个while中,要单独判别:i < j。

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转载自blog.csdn.net/zy2317878/article/details/80193419