Description
Given n non-negative integers a1, a2, ..., an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find
two lines, which together with x-axis forms a container, such that the container contains
the most water.
Note
You may not slant the container and n is at least 2.
Solution 1(C++)
class Solution {
public:
int maxArea(vector<int>& height) {
int water = 0;
int i = 0, j = height.size() - 1;
while (i < j) {
int h = min(height[i], height[j]);
water = max(water, (j - i) * h);
while (height[i] <= h && i < j) i++;
while (height[j] <= h && i < j) j--;
}
return water;
}
};
算法分析
这道题真没想到走的是实用主义。是我想太多了。
简单就好。积累积累吧。
程序分析
注意两个while中,要单独判别:i < j。