链表_A1074 Reversing Linked List (25 分)

https://pintia.cn/problem-sets/994805342720868352/problems/994805394512134144

/*
*链表逆置
*使用reverse()
*/
#include<iostream>
#include<algorithm>
#include<vector>
#include<cstdio>
using namespace std;
const int maxn = 1e5 + 10;
struct Node
{
    int add, data, next;
}node[maxn];
void init()
{
    for (int i = 0; i < maxn; i++)node[i].add = i;
}
int head, n, k;
vector<Node>list;
int main()
{
    scanf("%d%d%d", &head, &n, &k);
    init();
    for (int i = 0; i < n; i++)
    {
        int address;
        scanf("%d", &address);
        scanf("%d%d", &node[address].data, &node[address].next);
    }
    int p = head;
    while (p != -1)
    {
        list.push_back(node[p]);
        p = node[p].next;
    }
    int group = list.size() / k;
    for (int i = 0; i < group; i++)
    {
        reverse(list.begin() + i*k, list.begin() + i*k + k);
    }
    for (int i = 0; i < list.size(); i++)
    {
        printf("%05d %d ", list[i].add, list[i].data);
        if (i != list.size() - 1)printf("%05d", list[i + 1].add);
        else printf("-1");
        printf("\n");
    }
    return 0;
}