Codeforces 1080A. Petya and Origami

简单题，分别计算每种颜色需要的数量相加就行了

#include <bits/stdc++.h>
using namespace std;
int n,k,ans;
int main(){
	ios::sync_with_stdio(false);
	cin.tie(0);cout.tie(0);
	//freopen("data.in","r",stdin);
	//freopen("data.out","w",stdout);
	cin>>n>>k;
	ans += 2*n/k+(2*n%k==0?0:1)+5*n/k+(5*n%k==0?0:1)+8*n/k+(8*n%k==0?0:1); 
	cout<<ans;
	return 0;
}