CCPC-Wannafly Winter Camp Day1 (Div2, online mirror) A,B,E,F

https://www.zhixincode.com/contest/7/problems

A题

解析 分类讨论

#include<bits/stdc++.h>
#define all(a) (a).begin(),(a).end()
using namespace std;
typedef unsigned long long ull;
const int maxn=2e6+10;
int n,r,m,k,s;
int main()
{
    scanf("%d%d%d%d%d",&n,&r,&m,&k,&s);
    vector<int> x,y,zhuan{1,n};
    for(int i=0;i<r;i++)
    {
        int a,b;
        scanf("%d%d",&a,&b);
        if(a==s&&b==0)
            continue;
        if(b==0)
            x.push_back(a);
        else
            y.push_back(a);
    }
    sort(all(x));sort(all(y));
    while(m--)
    {
        int c;
        scanf("%d",&c);
        zhuan.push_back(c);
    }
    sort(all(zhuan));
    if(y.size()>0)
    {
        int l,r;
        if(x.size()==0)
            r=*(--y.end()),l=*y.begin();
        else
        {
            r=max(*(--x.end()),*(--y.end()));
            l=min(*x.begin(),*y.begin());
        }
        int ans1;
        for(auto it:zhuan)
            if(it<=l)ans1=it;
        int ans2=zhuan[lower_bound(all(zhuan),r)-zhuan.begin()];
        //cout<<ans1<<" "<<ans2<<endl;
        int ans=(ans2-ans1+k)*2;
        if(s<ans1)
            ans+=(ans1-s)*2;
        else if(s>ans2)
            ans+=(s-ans2)*2;
        cout<<ans<<endl;
        return 0;
    }
    x.push_back(s);
    sort(all(x));
    if(x.size()==1&&x[0]==s)
        cout<<0<<endl;
    else if(x[0]==s)
    {
        int ans=zhuan[lower_bound(all(zhuan),*(--x.end()))-zhuan.begin()];
        cout<<(ans-s)*2<<endl;
    }
    else if(*(--x.end())==s)
    {
        int ans;
        for(auto it:zhuan)
            if(it<=x[0])
                ans=it;
        cout<<(s-ans)*2<<endl;
    }
    else
    {
        int ans1,ans2;
        for(auto it:zhuan)
            if(it<=x[0])ans1=it;
        ans2=zhuan[lower_bound(all(zhuan),*(--x.end()))-zhuan.begin()];
        cout<<(ans2-ans1)*2<<endl;
    }
}

B题

dp

#include<bits/stdc++.h>
#define all(a) (a).begin(),(a).end()
using namespace std;
typedef unsigned long long ull;
const int maxn=10200;
int mp[20][20],dp[20][20][maxn];
int main()
{
    int n,m,C,xs,xt,ys,yt;
    scanf("%d%d%d",&n,&m,&C);
    for(int i=1;i<=n;i++)
        for(int j=1;j<=m;j++)
            scanf("%d",&mp[i][j]);
    scanf("%d%d%d%d",&xs,&ys,&xt,&yt);
    memset(dp,-0x3f,sizeof(dp));
    dp[xs][ys][0]=0;
    for(int k=1;k<maxn;k++)
    {
        for(int i=1;i<=n;i++)
        {
            for(int j=1;j<=m;j++)
            {
                dp[i][j][k]=max({dp[i-1][j][k-1],dp[i][j+1][k-1],dp[i+1][j][k-1],dp[i][j-1][k-1],dp[i][j][k-1]})+(k%mp[i][j]==0?1:0);
            }
        }
    }
    int ans=-1;
    for(int i=0;i<maxn;i++)
    {
        if(dp[xt][yt][i]>=C)
        {
            ans=i;
            break;
        }
    }
    printf("%d\n",ans);

}

E题 树形dp

#include <bits/stdc++.h>
#define pb push_back
#define mp make_pair
#define fi first
#define se second
#define all(a) (a).begin(), (a).end()
#define fillchar(a, x) memset(a, x, sizeof(a))
#define huan printf("\n")
#define debug(a,b) cout<<a<<" "<<b<<" "<<endl
#define ffread(a) fastIO::read(a)
using namespace std;
typedef long long ll;
const int maxn = 1e5+10;
const int maxm = 1e4+10;
const int inf = 0x3f3f3f3f;
const ll mod = 998244353;
const double epx = 1e-6;
const double pi = acos(-1.0);
//head------------------------------------------------------------------
struct edge
{
    int to,next;
}e[maxn];
int head[maxn],tot;
int dp[maxn][2],vis[maxn],f[maxn],d[maxn],n;
void init()
{
    tot=0;
    fillchar(head,-1);
    fillchar(vis,0);
}
void add(int u,int v)
{
    e[tot].to=v;
    e[tot].next=head[u];
    head[u]=tot++;
}
void dfs(int x,int y)
{
    vis[x]=1;
    dp[x][0]=0;
    dp[x][1]=f[x];
    for(int i=head[x];i!=-1;i=e[i].next)
    {
        int v=e[i].to;
        if(v==y)
            continue;
        dfs(v,x);
        dp[x][0]+=max(dp[v][0],dp[v][1]);
        dp[x][1]+=max(dp[v][0],dp[v][1]-d[min(x,v)]);
    }
}
int main()
{
    init();
    cin>>n;
    for(int i=1;i<=n;i++)
        cin>>f[i];
    for(int i=1;i<=n;i++)
        cin>>d[i];
    for(int i=2;i<=n;i++)
    {
        if(i%2==0)
            add(i/2,i),add(i,i/2);
        else if(3*i+1<=n)
            add(3*i+1,i),add(i,3*i+1);
    }
    int ans=0;
    for(int i=1;i<=n;i++)
        if(!vis[i])
        {
            dfs(i,-1);
            ans+=max(dp[i][1],dp[i][0]);
        }
    cout<<ans<<endl;
}

F最短路

#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<bitset>
#include<cassert>
#include<cctype>
#include<cmath>
#include<cstdlib>
#include<ctime>
#include<deque>
#include<iomanip>
#include<list>
#include<map>
#include<queue>
#include<set>
#include<stack>
#include<vector>
using namespace std;
typedef long long ll;
typedef long double ld;
typedef pair<int,int> pii;

const double PI=acos(-1.0);
const double eps=1e-6;
const ll mod=1e9+7;
const int inf=0x3f3f3f3f;
const int maxn=1e5+10;
const int maxm=100+10;
#define ios ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);

int n,m,k;
int cnt=0,head[maxn<<2];
bool vist[maxn];
ll dis[maxn],body[maxn];
priority_queue<pair<ll,int>,vector<pair<ll,int> >,greater<pair<ll,int> > >q;

struct node{
    int v,nex;
    ll w;
}edge[maxn<<2];

void add(int u,int v,ll w)
{
    edge[cnt].v=v;
    edge[cnt].w=w;
    edge[cnt].nex=head[u];
    head[u]=cnt++;
}

void dijkstra(int s)
{
    dis[s]=0;//到自己的最短距离直接设为0
    q.push(make_pair(0,s));
    while(!q.empty()){//队列非空
        int u=q.top().second;q.pop();
        vist[u]=true;
        for(int i=head[u];~i;i=edge[i].nex){
            int v=edge[i].v;
            ll w=edge[i].w+(body[v]>k?(body[v]-k)*(body[v]-k):0);
            if(dis[v]>dis[u]+w){//满足条件更新距离
                dis[v]=dis[u]+w;
                //p[v]=u;//保存路径
                q.push(make_pair(dis[v],v));//把更新完的值压入队列
            }
        }
    }
}

int main()
{
    memset(head,-1,sizeof(head));//初始化数组
    memset(vist,false,sizeof(vist));
    //memset(dis,inf,sizeof(dis));
    cin>>n>>m>>k;
    for(int i=0;i<=n;i++)//把距离初始化为 inf  不能用memset  自己估算一下路径最长有多长 inf定义大一点就好
        dis[i]=1e18;
    for(int i=1;i<=n;i++)
        cin>>body[i];
    for(int i=1;i<=m;i++){
        int u,v;ll w;
        cin>>u>>v>>w;
        add(u,v,w);
        add(v,u,w);//无向图相互可达 有向图一次就好
    }
    k+=body[1];
    dijkstra(1);
    cout<<dis[n]<<endl;

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转载自www.cnblogs.com/stranger-/p/10453063.html