UVA10305_OrderingTask(简单的拓扑排序)

#include<bits/stdc++.h>
using namespace std;

const int maxn = 100 + 5;
int m, n;
int G[maxn][maxn];
int top[maxn], cnt;
int vis[maxn];

void dfs(int u)
{
    vis[u] = 1;
    for(int i = 1; i <= n; i++){
        if(G[u][i] && !vis[i]){
            dfs(i);
        }
    }
    top[--cnt] = u;
}

void solve()
{
    cnt = n;
    memset(vis, 0, sizeof(vis));
    for(int i = 1; i <= n; i++){
        if(!vis[i]){
            dfs(i);
        }
    }
    cout << top[cnt];
    for(int i = cnt + 1; i < n; i++){
        cout << " " << top[i];
    }
    cout << endl;
}


int main()
{
    while(cin >> n >> m && m && n){
        memset(G, 0, sizeof(G));
        for(int i = 0; i < m; i++){
            int u, v;
            cin >> u >> v;
            G[u][v] = 1;
        }
        solve();
    }
    return 0;
}

一个坑：题目说的是以0 0结尾，但是while(cin >> n >> m && n && m) 无法AC，只能是while(cin >> n >> m && n)