c# Leetcode 448. 找到所有数组中消失的数字 (回顾)

常规思想答案

不满足时间复杂度为O(n) 的答案:

		public static IList<int> FindDisappearedNumbers(int[] nums)
		{
			List<int> res = new List<int>();
			var len = nums.Length;
			for (int i = 1; i <= len; i++)
			{
				if (!nums.Contains(i))
				{
					res.Add(i);
				}
			}
			return res; 
		}

 诡异的思想答案:

击败90.00%

public static IList<int> FindDisappearedNumbers(int[] nums)
		{
		    var res = new List<int>();
			for (int i = 0; i < nums.Length; i++)
			{
				int index = Math.Abs(nums[i]) - 1;
				if (nums[index]>0)
				{
					nums[index] = -nums[index];
				}
				if (nums[index]>0)
				{
					nums[index] = -nums[index];
				}
			}
			for (int i = 0; i < nums.Length; i++)
			{
				if (nums[i]>0)
				{
					res.Add(i + 1);
				}
			}
			return res; 
		}

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转载自blog.csdn.net/us2019/article/details/86546911