[LeetCode&Python] Problem 268. Missing Number

Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array.

Example 1:

Input: [3,0,1]
Output: 2

Example 2:

Input: [9,6,4,2,3,5,7,0,1]
Output: 8

Note:
Your algorithm should run in linear runtime complexity. Could you implement it using only constant extra space complexity?

class Solution(object):
    def missingNumber(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        if 0 not in nums:
            return 0
        m=max(nums)
        s=sum(nums)
        ms=(m+1)*m/2
        if ms==s:
            return m+1
        return (m+1)*m/2-sum(nums)

  

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转载自www.cnblogs.com/chiyeung/p/10080400.html