Given an array containing n distinct numbers taken from 0, 1, 2, ..., n
, find the one that is missing from the array.
Example 1:
Input: [3,0,1]
Output: 2
Example 2:
Input: [9,6,4,2,3,5,7,0,1]
Output: 8
Note:
Your algorithm should run in linear runtime complexity. Could you implement it using only constant extra space complexity?
class Solution {
public:
int missingNumber(vector<int>& nums) {
if (nums.empty())
return 0;
int sum = 0, n = nums.size();
for (int i = 0; i < nums.size(); i ++)
sum += nums[i];
return n*(n+1)/2 - sum;
}
};